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Material Science Homework Help From The Top Materials Science Tutor!

Materials science is an interdisciplinary field that provides an understanding of the underlying structure & properties of matter. This subject also incorporates the study of the application of materials and their performance. This subject applies the laws of physics, chemistry, and mathematics to study material concepts such as structures, behaviors, and characteristics. Studying such subjects requires proper guidance from experts. The reason students are nowadays opting for Material Science homework help.

For pupils to grasp this topic alone becomes highly intimidating. Students frequently struggle with the complexity of the subject and look for a reliable materials science tutor. Common searches include "Can someone give me answers to material science questions?" and "Can someone provide me materials science tutoring?" But your search is over right here. Yes, TutorBin offers the best materials science tutoring by the best materials science tutors. Follow this comprehensive blog to know more about how TutorBin aids millions of students in achieving their dreams.

Material Science Homework Help @ TutorBin

Topics	Benefits
Thermodynamics of materials	Expert tutors
EPM	Pocket-friendly prices
Mechanics	100% original and accurate answers

Subjects Our Material Science Tutor Cover!

It is one of the most interdisciplinary subjects that combines knowledge of physics, thermodynamics, material science, fluids, mechanics, experimental chemistry, and MATLAB. Check the list of the topics that our materials science tutor covers.

Thermodynamics of materials: The thermodynamics of materials is one of the most crucial issues in the material sciences and engineering field. The topic of material thermodynamics conveys very fundamental equations created by the materials and the creation of their structure. Because it covers all the essential information that will pave the road for their engineering careers throughout their lives, this subject is truly the foundation of the material science and engineering department.

This subject is about studying the fundamental terms presented to you, understanding the structure of every piece of information down to its smallest unit, and then learning to connect those pieces using mathematical equations or theorems.

EPM: Electromagnetic Properties of Materials is EPM. It is appropriate for achieving a good GPA because it primarily consists of the theory portion. Although it is a simple subject to score well on, its importance is on par with that of the other concepts. Ferro and Electro are the two main magnetism-related topics in the Material Sciences.

Mechanics: The subject's name speaks for itself; it depends on how well a student understands the varied mechanics of various materials available worldwide. The majority of mechanical engineering comprises this subject.

The Process To Find The Best Materials Science Tutoring!

You never have to worry about the "material science solution" quality with TutorBin's material science homework help. We have a comprehensive framework that our materials science tutor follows to craft your homework. Here is a description of the process:

Order placement: This is the first step in getting homework help from a material science tutor. Login to our website or use our app to post your question there. Describe your homework in full, provide any particular needs or instructions to follow, and let us know when it is due.

Assessing homework requirements and giving a quotation: Our representative will get in touch with you with a price quotation after we know your required files and thoroughly understand your specific instructions. We always try our best to provide you with a reasonable price quotation.

Assigning the academic writing expert: We ensure that our quality control team reads the homework specifications before hiring a material science tutor for your homework. They select a competent material science tutor depending on your task's complexity.

Research and Information Gathering: Our educational specialist will next begin working on your "material science solution manual." He will start the research process to obtain the primary data and information.

Writing the solutions: Once our material science writer has completed the basic research and has all the required information, he begins composing your homework to the best of his expertise. You will receive 100% original and precise material science solutions to your problem.

Quality Check: Once the writing team has completed your applied material science answers, the editing team takes charge. It verifies the quality and guarantees that it complies with all of the project's particular needs following the guidelines provided to the pupils. They return it to the writer, who makes the appropriate modifications if they find any sections that need improvement.

Delivery: The work is approved once the quality control team finds that it complies with our company's quality requirements. Then we will deliver your material science solution for final submission.

Revision: This is the last step of the material science homework help. If you need any content modifications after getting it, contact us. It can include changing the reference or redoing the homework. To meet tight deadlines, we have a team of knowledgeable writers. We prioritize completing such jobs as soon as we can.

Material Science Homework Help From TutorBin - 6 Benefits!

TutorBin’s material science homework help benefit students immensely. We have discussed the reasons below. See why students recommend our help with material science homework.

Authenticity and precision: At TutorBin, we have a group of specialists with backgrounds in mechanical engineering. They are highly skilled at determining the solutions to material science problems. This service will provide you with the advantages of authenticity and accuracy, which are quite beneficial. You may be confident that the work will be of excellent quality.

Time commitment: TutorBin's material science experts understand how crucial it is to turn in homework on time. As a result, you will never miss the submission deadline.

Critical hour support:Whom will you call if you have an urgent deadline to submit material science homework? The most reliable option is TutorBin. Our company is best known for helping millions of students even at odd hours. Our material science experts provide solutions around-the-clock.

Original content with a detailed explanation: Our tutors carefully analyze material science questions before providing answers with thorough explanations. We guarantee that each material science solution you take from us will make it easier for you to understand all the foundational theories.

Prices are reasonable: We offer services at economical prices. You won't feel pressured to spend a fortune as long as TutorBin is in charge of providing you with material science solutions. Our main goal is to enhance student progress while offering affordable tuition to meet the needs of all students.

Expertise: All mechanical engineers are qualified individuals. They have much knowledge in helping students from different grade levels and nations with their engineering homework (basic, intermediate, and advanced). When you inquire, "Can I pay someone to do my material science homework?" they provide the best assistance. If you collaborate with our specialists during your study period, we promise you will get top grades.

Where Can I Find The Best Materials Science Tutors? TutorBin Is The Place!

Are you looking for a dependable service when you ask, "Can I hire someone to do my material science homework?" Have you been working on material science questions for countless hours? Connect with one of our materials science tutors to get a real-time, on-site response. You don't have to put in any more effort than is necessary. TutorBin offers a distinctive materials science tutoring experience. Like many other services, we employ material science specialists with advanced engineering degrees rather than undergraduate students.

We offer 24/7 access to our online material science tutoring and homework assistance services every day of the week. Our materials science tutors will take you through the material science answers step-by-step. Thus, your comprehension of this topic will improve. We also make it simple for you to receive support because of our simple request method. There won't be any delays in the delivery services you obtain. There are no hidden fees or recurring charges, and our price is fair and open. Why then wait any longer? Come to us right away if you need help! Cheers!

FAQs Searched By Students

How much does TutorBin charge for materials science tutoring?

Our fees for material science tutoring depend on several factors. Our prices vary depending on the subjects, amount of homework, level of difficulty, and proximity to the due date.

Does TutorBin provide material science answers for free?

We have highly educated and experienced material science experts. As a result, we charge for the answers. We do not provide free material science homework help as we compensate them for their time and efforts. However, you can bear our economical price.

How long will a material science tutor take to provide homework solutions?

We encourage you to establish a deadline to receive material science solutions on time. But the complexity and deadline will determine the time taken to provide material science answers.

Where can I get the material science solved examples?

If you need solved examples, don't hesitate to contact material science homework help for assistance. But before you hire someone to help you with material science homework, think about the following aspects:

A short turnaround time
Quality assurance
Eminent tutors with experience
Affordable prices

We are pleased to inform you that TutorBin possesses all these features to help you obtain precise material science solved examples.

Why should I pay TutorBin to do my material science homework?

TutorBin includes several features that make it an excellent website for material science solutions.

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Until you are pleased with your coursework, we revise your content at no cost to you.
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Can I get Original work solutions from TutorBin's materials science tutors?

Our materials science tutors make the following efforts to ensure original work while offering help with material science homework:

Cite your sources correctly
Make effective use of quotations and paraphrases
Proofread and edit the paper

How do I get homework help from a materials science tutor at TutorBin?

If you're looking for help from a materials science tutor at TutorBin, you can take the following steps:

Firstly, TutorBin is a good place for reliable material science homework help.
Please specify whether you require material science homework help, video solutions, or live teaching.
Create an account for free and post your question: "Can you do my material science homework?" Don't hesitate to contact us at 7082686818 or tutors@tutorbin.com for emergency material science help, even at odd hours.
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Recently Asked Material Science Questions

Expert help when you need it

Q1: 1. Label the following as positive or negative. (5 pts) a) (C b) c) d) See Answer
Q2: 1) Determine the diameter of the pin which will provide a factor of safety of 1.5 guarding against yielding [9 Marks] Part (a) of the figure below shows a knuckle joint with a pin inside it. This joint is subject to a fluctuating load F varying between 0 N and 6000 N in tension. Assume the loading on the rotatable pin is modeled as concentrated force as shown in part (b) of the figure (Free-body-diagram). The shaft is made from AISI1018 hot-rolled steel that was machined to its final diameter. The fatigue stress concentration factor is set to unity. Based on a stress element on the outer surface at the cross-section A:See Answer
Q3: A cylindrical specimen of a brass alloy having a length of 96 mm (3.780 in.) must elongate only 4.80 mm (0.1890 in.) when a tensile load of 90000 N (20230 lb;) is applied. Under these circumstances what must be the radius of the specimen? Consider this brass alloy to have the stress-strain behavior shown in the Animated Figure 6.12.See Answer
Q4: An alloy to be used for a spring application must have a modulus resilience of at least 0.82 x 10 J/m (0.82 x 10° Pa). What must beits minimum yield strength (in MPa)? Assume that the modulus of elasticity for this alloy is 101 GPa.See Answer
Q5: A cylindrical rod of copper (E = 110 GPa, 16 x 106 psi) having a yield strength of 240 MPa (35,000 psi) is to be subjected to a load of 6650 N (1495 lbp). If the length of the rod is 370 mm (14.57 in.), what must be the diameter to allow an elongation of 0.52 mm(0.02047 in.)?See Answer
Q6: Arrange the following cross-section in order of increasing second area moment about their respective horizontal axes. Assume that each cross-section has the same area. (5 pts) See Answer
Q7: Linda obtained the stress-strain curves of three different materials, A, B, and C as given below. Please answer the following question. Which material is the stiffest? A B CSee Answer
Q8: Determine the Miller indices for the planes shown in the following unit cell (a=b=c). (+8) See Answer
Q9: If the specific surface energy for soda-lime glass is 0.30 J/m2, using data contained in Table 12.5, compute the critical stress (in MPa) required for the propagation of a surface crack of length 0.05 mm. See Answer
Q10: Here is a schematic portion of extrinsic semiconductor (Si dopedwith boron (B)) showing the valence electron distribution. Thisextrinsic semiconductor is formed by pre-deposition of B and drive-in diffusion methods. B is first introduced to Si by pre-depositionstep following the Fick's second rule. During this doping step, thesurface concentration of B remained constant as 5.44 ×1025 atoms/m3 and B atoms diffused into Si at 1200°C for 10 h.The concentration profile of B follows the equation given below.The background concentration of B (Co) in Si is 2 x 1019 atoms/m³. surface concentration of B remained constant as 5.44 x1025 atoms/m³ and B atoms diffused into Si at 1200°C for 10 h.The concentration profile of B follows the equation given below.The background concentration of B (Co) in Si is 2 x 1019 atoms/m3. What is the concentration (atoms/m3) of B at 2 um below thesurface of Si? (+15)See Answer
Q11: Q4 Phosphorus atoms are to be diffused into a silicon wafer using both predeposition and drive-in heat treatments;the background concentration of Pin this silicon material is known to be 5 × 1019 atoms/m³. The predeposition treatment is to be conducted at 950°C for 45 minutes; the surface concentration of P is to be maintained at a constant level of 4.5 × 1026 atoms/m³. Drive-in diffusion will be carried out at 1200°C for a period of 2.5 h. For the diffusion of P in Si, values of Qa and Do are 3.40 eV and 1.1 × 10^-4 m²/s, respectively.To solve this problem, you will need to make yourself familiar with equations 5.11, 5.12 and 5.13 from the book: C(x, t)=\frac{Q_{0}}{\sqrt{\pi D t}} \exp \left(-\frac{x^{2}}{4 D t}\right) Q_{0}=2 C_{s} \sqrt{\frac{D_{p} t_{p}}{\pi}} x_{j}=\left[\left(4 D_{d} t_{d}\right) \ln \left(\frac{Q_{0}}{C_{B} \sqrt{\pi D_{d} t_{d}}}\right)\right]^{1 / 2} Equation 5.11 (Solution for Fick's 2nd law for drive- in diffusion) Equation 5.12 (predeposition) Equation 5.13 (drive-in diffusion) a) Calculate the value of Qo (total amount of impurities). (3 marks) b) Determine the value of xj (junction depth) for the drive-in diffusion treatment. (3 marks) c) Also, for the drive-in treatment, compute the position x at which the concentration of P atoms is 10^24 m^-3.(3 marks)See Answer
Q12: A tension test of a material results in the stress-strain diagram below. See Answer
Q13: 5. In order to design the geometry of a mold cavity, total solidification time needs to be calculated for the directional solidification. For the design in figure below, the Tst (riser)=10 min. (9') (1) Select a choice below with suitable TSTfor the sphere and the cube that satisfiesdirectional solidification: (a) Tst (cube) = 5min, Tst (sphere)7min; (b) Tst (cube)5min;= 7min, TST (sphere)= O Based on your selection, if riser is the cylinder with height of 0.1m and diameter of 0.1m, calculate theradius r of the sphere and the side length a of the cube, respectively. (Assume Cm is a constant, n=2)See Answer
Q14: Q7 Nichrome materials are alloys consisting of Nickel and Chromium. They are widely used for resistant heating wires in applications like toasters, space heaters or hair dryers. Answer the following questions about the Ni-Cr phase-diagram shown below. Express all compositions as Cr-x wt.% Ni, e.g. the eutectic composition (which is explicitly shown in this particular diagram) would be written as Cr-49 wt.% Ni. a) Label all regions on the phase diagram with their corresponding phases, using the following labels: \begin{array}{l} \mathrm{L} \\ \alpha(\mathrm{Cr}) \\ \beta(\mathrm{Ni}) \\ \mathrm{Ni}_{2} \mathrm{Cr} \end{array} b) Consider a composition of Cr-22 wt.% Ni. What is the chemical composition (in wt.%) of the very first solid to appear in a liquid alloy of this overall composition that is cooled slowly from 1800°C.? (2 mark) c) At what temperature does this solid begin to form in the liquid? (1 mark) d) For the same composition alloy: (3 marks) e) For the same alloy: (3 marks) I.What are the compositions (in wt.%) of the two phases present at 1600°C? II.What are the relative fractions of the two phases that are present at 1600°C? I.What are the compositions (in wt.%) of the two phases present at 900°C? II.What are the relative fractions of the two phases that are present at 900°C? f) What is the lowest temperature a fully liquid Cr-Ni alloy can exist at and what is the composition of that liquid? (1 mark)See Answer
Q15: A cylindrical specimen of aluminum having a diameter of 12.8 mm and a gauge length of50.800 mm is pulled in tension. Use the load-elongation characteristics shown in the following table to determine the following: (a) Plot the data as engineering stress versus engineering strain (using excel sheet and plots). (b) Compute the modulus of elasticity. (c) Determine the yield strength at a strain offset of 0.002. (10 (d) Determine the tensile strength of this alloy. ( (e) What is the approximate ductility, in percent elongation? ( (f) Compute the modulus of resilience. (5 See Answer
Q16: A bar of a steel alloy that exhibits the stress-strain behavior shown in the Animated Figure 6.22 is subjected to a tensile load; the specimen is 375 mm (14.8 in.) long and has a square cross section 5.5 mm (0.22 in.) on a side. (a) Compute the magnitude of the load necessary to produce an elongation of 0.525 mm (9.021 in.). (b) What will be the deformation after the load has been released?See Answer
Q17: A large plate is fabricated from a steel alloy that has a plane strain fracture toughness of 55 MPa v m (50 ksivin.)55 MPam (50 ksiin.). If, during service use, the plate is exposed to a tensile stress of 200 MPa (29,000 psi) determine the minimum length (in m) of a surface crack that will lead to fracture. Assume a value of 1.0 for Y. See Answer
Q18: Progress For the tempered steel alloy whose stress-strain behavior can be observed in the "Tensile Tests" module of Virtual Materials Science and Engineering (VMSE), determine the following: (a) the approximate yield strength (0.002 strain offset), (b) the tensile strength, and (c) the approximate ductility, in percent elongation.See Answer
Q19: Find the toughness (or energy to cause fracture) for a metal that experiences both elastic and plastic deformation. Assume Equation6.5 for elastic deformation, that the modulus of elasticity is 172 GPa (25 x 10° psi), and that elastic deformation terminates at a strain of 0.010. For plastic deformation, assume that the relationship between stress and strain is described by Equation 6.19, in which the values for K and n are 6900 MPa (1x 106 psi) and O.28, respectively. Furthermore, plastic deformation occurs between strain values of 0.010 and 0.72, at which point fracture occurs.See Answer
Q20: The maximum recommended speed for a 250-mm-diameter abrasive grinding wheel is 2000 rev mii.Assume that the material is isotropic; use a bore of 20 mm, v =0.24, and a mass density of3320 kg/m', and find the maximum tensile stress at this speed.See Answer

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