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# ≤fyc-

EM A=

Ay-40-30-2000

Joint A

{FX=0

BX

{fy="

Ax

4.3 (Joint)

५०

Ay= 90 kN

120

Ay

-Bx+Ax+15=0

Bx (4) - 40X3-30×6-20x9-15xy=0

BX= 135KN

AG+120=8

AB

qo

Ав+ досе

r

да

20

Sex

915

Bx · Ax=-15+135

Ax= 120KN

AG₂-120KN

AB₂-90KN

7

(C)

CS CamScanner Joint E

{Fy=0

Jolint D

0=lan² (77= 53.13

1

{FX

Joint

Σfycv (DF=0

cu

·EF Sin 53.13- 2000

CD + DE=v

F

DE

4₁3,

CD= 30KN

EF Cos53 13 +15=0

DE = 115²~(~25) Cuss 3.13

OF

(T)

се

Pase #2

CD

GF

£

A

20

EF

DE

53.13

≤f you

-30-255 in 53.13+CF s'in 53.18=0

CF = 62-5KN

EF=-25 KN

DF

کاد

J F

53113

(T)

DE = 30KN

(T)

DE

#f=~25

)٢(

-25 cos 53.13-62.5 cos 53.13-GF=o

(GF = -52.5KN

٠٢٢١

CS CamScanner Joint B

отхуз

135 е

вао 112,5kN

120

135

Jolint &

Екупо

62.5 sin 53-13- сасо

Саг-50 kN

- до

n

(4,3)

т

до

В

п

до

вс

ва 67,5

Разеа з

135+ 112.5 cos 53, 13+ всео

67,5 kN

вс

bestes

112.5

ха

1

50

1 53,13

-120

чо

зо

вс

с

53.13

тата

Ga

62.5

вс

- 52.5

зо

30

ск. 62-5

-25

20

15

CS CamScanner 4.3 (Section)

≤Fy₁0

Ay-40-30-2000

Адочоки

Take

BX

6-9

EMA-O

५०

40X 3+30X 6+20x4 + 15 X 4-BX (4) - 0

здох

Вес 135 ки

AX₂ 120+N

2

'Ag`

0x Tan ¹ ( 1 ) - 57.13 DE J

3

CF y co

Take b-b'

EMF-0

CD (4) 20X3-15x400

EMF-0

15X4+20X3- DE (4/00

DE

зоки

-20 - EFSM 531/3==

CD= 30 KN TI

d

(T)

с

(cfr

1

EMC=0

G₁F (4) + 301 3+2016=0

Екупо

s

GAS

6

53.136

-

br

-3-

3-

-

CF Sin 53.13-30=28=0

CF = 62.5KN

30

р

A

20

Ef ₂-

2

30

-

(T)

کا

20

-3.

20 4

GFz-52.5KN

25KN

کاد

(9)

CS CamScanner Take d-d

Ef gro

-96-30-200

са

Емаг

Take <- 6

{Fy=

EMBRO

вс ал

Take e e

Емаю

7

ca

CG=-SokN

BC (Y)- 30x3-20x6-15x400

BC= 67,5KN

120

стар

135 €

90-BG51453.13=0

BG ₂112-5/N

120

e

3-

d

१०

AG (4) + 120X Mo

AB

AB (3) +9013/00

B

Aq

30

53,13

(T)

6

3.

→AG

ว-

R

BC)

c'

20

15

T

AG=-120/N

Ahme

ABE- 90 KN) (C)

)(C)

CS CamScanner

T/n!!!

<>

I

(h)

4 m

A

P4.3 and P4.4. Determine the forces in all bars

of the trusses. Indicate tension or compression.

16 kips

24 kips

P4.2

c

40 kN

P4.3

P4.4

36 kips

E

20 KN

24 kips 12

Aa

P4.5 to P4.10. Determine the forces in

Ĝ

Page 160

Fig: 1