Given, forward drop voltage =1.2V And diode resistance =250hm For only diode drop \text { Current }=\frac{\text { Supply voltage - Diode drop }}{\text { load resistance }}=\frac{6-1.2}{120}=0.04 \mathrm{~A} For diode drop and resistance included \text { Current }=\frac{\text { Supply voltage-Diodedrop }}{\text { load resistance }+\text { diode resistance }}=\frac{6-1.2}{120+25}=0.0331 \mathrm{~A}

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