Lula is trying to find and classify the discontinuities of some functions, but she has some misconceptions.In this problem, your job is to explain what’s wrong with Lula’s reasoning. "As

x → 3, the denominator x – 3 tends to 0; there's nothing that I can cancel in the numerator and denominator, so g must have a vertical asymptote at x = 3." - What is incorrect about Lula's reasoning? Is Lula's conclusion that g has a vertical asymptote at x = 3 correct? Give a concrete example to show Lula that her reasoning is incorrect. (In other words, give a different function g for which the same reasoning would lead Lula to the wrong conclusion.) next, lula looks at g(x) cos/x-3 she recognizes that there is a discontinuity at x=3 and she says