PROBLEMS 5.60 An adventurous archaeologist crosses between two rock cliffs by slowly going hand over hand along a rope stretched between the cliffs. He stops to rest at the middle of

the rope (Fig. P5.60). The rope will break if the tension in it exceeds 2.50 x 10° N, and our hero's mass is 90.0 kg. (a) If the angle 8 is 10.0°, what is the tension in the rope? (b) What is the smallest value can have if the rope is not to break? Figure P5.60/nL In the given question first law of equilibrium in physices is applicable. It means net force on the system must be zero. 2 Friet = 0 Smallest angle Ⓒ. Assuming. T and my is the weight of TEA F.G.D. of the system. Taine TELO Je T An equilibrium Loma CASA ту is TE atAing = mg T=ma [mathematical for m physicas low 2sing the tension in cable. ≤fy=0 + Tsina-mg = 0 From above part 90x9.81 2 fin lo T= 2542-21 N 2 Tsino = mg spn = ma 2.T @ = sint min (= sin-1 (m ² ) mg min 27 90x9.81. ( our Hero. Omin = 1.012° :) 2x 2.5x104. Zoom Out