PROBLEMS

5.60 An adventurous archaeologist crosses between two rock

cliffs by slowly going hand over hand along a rope stretched

between the cliffs. He stops to rest at the middle of the rope

(Fig. P5.60). The rope will break if the tension in it exceeds

2.50 x 10° N, and our hero's mass is 90.0 kg. (a) If the angle 8

is 10.0°, what is the tension in the rope? (b) What is the smallest

value can have if the rope is not to break?

Figure P5.60/nL

In the given question first law of equilibrium

in physices is applicable.

It means net force on the system must be

zero.

2 Friet = 0

Smallest

angle

Ⓒ. Assuming. T

and my is the weight of

TEA

F.G.D. of the system.

Taine

TELO

Je T

An equilibrium

Loma CASA

ту

is

TE

atAing = mg

T=ma

[mathematical for m

physicas low

2sing

the tension in cable.

≤fy=0

+ Tsina-mg = 0

From above part

90x9.81

2 fin lo

T= 2542-21 N

2 Tsino = mg

spn = ma

2.T

@ = sint

min

(= sin-1 (m ² )

mg

min

27

90x9.81.

(

our Hero.

Omin

= 1.012°

:)

2x 2.5x104.

Zoom Out