Question 1 > Graphing Quadratic Functions Use your graphing calculator to help you determine the number and type of solutions to the Quadratic Equation 2x² - 10 = 8x 1. Begin by putting the equation into standard form. 2. Graph the function on your calculator. [Hint: Use the following window on your graphing calculator: Xmin = -6, Xmax = 10, Ymin = -23, Ymax = 5] 3. IF your solutions are real number solutions, use the graphing INTERSECT method to find them. 4. Draw the parabola neatly below by plotting the highest (or lowest) point and one other point. 5. Place a point on the graph at each of the Horizontal Intercepts, if any 6. Below the graph, identify the number of Real Solutions and identify those solutions Graph the function and plot the Horizontal Intercepts: ŝ Use your graphing calculator to help you determine the number and type of solutions to the Quadratic Equation 2x2 - 10 - 8x 1. Begin by putting the equation into standard form. 2. Graph the function on your calculator. [Hint: Use the following window on your graphing calculator: Xmin = -6, Xmax = 10, Ymin = -23, Ymax = 5] 3. IF your solutions are real number solutions, use the graphing INTERSECT method to find them. 4. Draw the parabola neatly below by plotting the highest (or lowest) point and one other point. 5. Place a point on the graph at each of the Horizontal Intercepts, if any 6. Below the graph, identify the number of Real Solutions and identify those solutions Graph the function and plot the Horizontal Intercepts: -10 -12- -13 -14 -16 -18 -19 -20- -21 -22- 8 9 10 -8 -9 -20 -12- -13 -14- -15- -16 -18 -19 -20 -21 -22+ -23- Clear All Draw: Identify the number of Real Solutions (0, 1 or 2): Identify the Real Solutions rounded to two decimal places: x = [Hint: If two solutions exist, enter the answer as a, b. If only one solution exists, enter a. If none exist, enter DNE. Question 3 Let 1 = Solve the quadratic equation -5x² 20x = 0 by using the Quadratic Formula. Write your answers in Exact Form and in Approximate Form (Rounded to three decimal places as needed). Note that in some cases, the Exact Form and the Approximate Form may be the same. x1 = -b-√b² - 4ac x1 = 2a < > Exact Form II. DE Solving Quadratic Equations Note: If only one solution exists, x2 will equal DNE -5x² 20x = 0 Dvd and x2= Approximate Form = -b+ √b² - 4ac 2a x2 = x2 = Exact Form Approximate Form Question 4 Solving Quadratic Equations Solve the quadratic equation 4x2 +25=-20x by using the Quadratic Formula. Write your answers in Exact Form and in Approximate Form (Rounded to three decimal places as needed). Note that in some cases, the Exact Form and the Approximate Form may be the same. Let x1 = x1 = -b-√b² - 4ac x1 = 2a Note: If only one solution exists, x2 will equal DNE 4x² + 25 = -20x 2a Question Help: and 2 Exact Form Approximate Form = -b+√b² - 4ac Video Message instructor x2 = x2 = Exact Form Approximate Form

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