question 1 greater than graphing quadratic functions use your graphing

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Question 1
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Graphing Quadratic Functions
Use your graphing calculator to help you determine the number and type of solutions to the Quadratic
Equation 2x² - 10 = 8x
1. Begin by putting the equation into standard form.
2. Graph the function on your calculator. [Hint: Use the following window on your graphing
calculator: Xmin = -6, Xmax = 10, Ymin = -23, Ymax = 5]
3. IF your solutions are real number solutions, use the graphing INTERSECT method to find them.
4. Draw the parabola neatly below by plotting the highest (or lowest) point and one other point.
5. Place a point on the graph at each of the Horizontal Intercepts, if any
6. Below the graph, identify the number of Real Solutions and identify those solutions
Graph the function and plot the Horizontal Intercepts:
ŝ Use your graphing calculator to help you determine the number and type of solutions to the Quadratic
Equation 2x2 - 10 - 8x
1. Begin by putting the equation into standard form.
2. Graph the function on your calculator. [Hint: Use the following window on your graphing
calculator: Xmin = -6, Xmax = 10, Ymin = -23, Ymax = 5]
3. IF your solutions are real number solutions, use the graphing INTERSECT method to find them.
4. Draw the parabola neatly below by plotting the highest (or lowest) point and one other point.
5. Place a point on the graph at each of the Horizontal Intercepts, if any
6. Below the graph, identify the number of Real Solutions and identify those solutions
Graph the function and plot the Horizontal Intercepts:
-10
-12-
-13
-14
-16
-18
-19
-20-
-21
-22-
8
9
10 -8
-9
-20
-12-
-13
-14-
-15-
-16
-18
-19
-20
-21
-22+
-23-
Clear All Draw:
Identify the number of Real Solutions (0, 1 or 2):
Identify the Real Solutions rounded to two decimal places: x =
[Hint: If two solutions exist, enter the answer as a, b. If only one solution exists, enter a. If none exist,
enter DNE. Question 3
Let 1 =
Solve the quadratic equation -5x² 20x = 0 by using the Quadratic Formula. Write
your answers in Exact Form and in Approximate Form (Rounded to three decimal places
as needed). Note that in some cases, the Exact Form and the Approximate Form may be
the same.
x1 =
-b-√b² - 4ac
x1 =
2a
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Exact Form
II.
DE
Solving Quadratic Equations
Note: If only one solution exists, x2 will equal DNE
-5x² 20x = 0
Dvd
and x2=
Approximate Form
=
-b+ √b² - 4ac
2a
x2 =
x2 =
Exact Form
Approximate Form Question 4
Solving Quadratic Equations
Solve the quadratic equation 4x2 +25=-20x by using the Quadratic Formula. Write
your answers in Exact Form and in Approximate Form (Rounded to three decimal places
as needed). Note that in some cases, the Exact Form and the Approximate Form may be
the same.
Let x1 =
x1 =
-b-√b² - 4ac
x1 =
2a
Note: If only one solution exists, x2 will equal DNE
4x² + 25 = -20x
2a
Question Help:
and 2
Exact Form
Approximate Form
=
-b+√b² - 4ac
Video Message instructor
x2 =
x2 =
Exact Form
Approximate Form