\text { Let } c \text { be a constant. For what value(s) of } c \text { is the integral } \int_{c}^{2} \frac{-1}{x+1} d x \text { improper? (i.e.

} for what c value(s) would we need to use the Type 2 Improper Integral techniques to solve OThis integral is never improper. All c on the interval (-infinity, -1]. All c on the interval (-infinity, infinity). O All c on the interval [-1, infinity). The only constant which makes this integral improper is c = -)