} for what c value(s) would we need to use the Type 2 Improper Integral techniques to solve OThis integral is never improper. All c on the interval (-infinity, -1]. All c on the interval (-infinity, infinity). O All c on the interval [-1, infinity). The only constant which makes this integral improper is c = -)
Fig: 1
Fig: 2
Fig: 3
Fig: 4
Fig: 5
Fig: 6
Fig: 7