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b. A conducting wire is shaped like a half-circle as shown in the figure, with linear charge density λ. You may assume the electric field components in the x-direction all cancel, al-though in the y-direction they do not. The total electric field strength at P will be the integral of each component dE caused by a charge dq going around the arc from angle Theta = 0 to Theta = π. i) Write an expression that fills in the gap below, in terms of the radius r and the permittivity of free space:

dE= __________dq

ii) Write an expression for the y-component only of the electric field caused by charge dq at position Theta on the conducting wire.

iii) Write out an expression for the charge component dq in terms of a small change in angle around the arc: dq=______dTheta

iii) Showing your work, write the electric field vector at the point P.

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