Find the toughness (or energy to cause fracture) for a metal that experiences both elastic and plastic deformation. Assume Equation6.5 for elastic deformation, that the modulus of elasticity is 172

GPa (25 x 10° psi), and that elastic deformation terminates at a strain of 0.010. For plastic deformation, assume that the relationship between stress and strain is described by Equation 6.19, in which the values for K and n are 6900 MPa (1x 106 psi) and O.28, respectively. Furthermore, plastic deformation occurs between strain values of 0.010 and 0.72, at which point fracture occurs.

Fig: 1